地址点击打开链接
很简单,合并两个单链表,书上的内容
答案:
# Definition for singly-linked list.
# class ListNode(object):
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution(object):
def mergeTwoLists(self, l1, l2):
"""
:type l1: ListNode
:type l2: ListNode
:rtype: ListNode
"""
if l2 == None:
return l1
if l1 == None:
return l2
if l1.val >= l2.val:
head = l2
l2 = l2.next
else:
head = l1
l1 = l1.next
curNode = head
while l1 and l2:
if l1.val >= l2.val:
curNode.next = l2
curNode = curNode.next
l2 = l2.next
else:
curNode.next = l1
curNode = curNode.next
l1 = l1.next
if not l1:
curNode.next = l2
if not l2:
curNode.next = l1
return head
本文介绍了一种合并两个有序单链表的方法,并提供了一个Python实现示例。通过定义一个链表节点类和解决方案类,实现了合并操作,确保了合并后的链表依然有序。
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