UVA:10071 - Back to High School Physics

最新推荐文章于 2022-12-02 20:39:05 发布

原创最新推荐文章于 2022-12-02 20:39:05 发布 · 379 阅读

0 ·

CC 4.0 BY-SA版权

UVA 专栏收录该内容

4 篇文章

订阅专栏

本文提供了一种简单的方法来计算在已知初速度和加速度的情况下，粒子在两倍于达到某一速度所需时间内的位移。通过给出的C++代码示例，可以直接计算出所需的位移值。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

A particle has initial velocity and constant acceleration. If its velocity after certain time is v then what will its displacement be in twice of that time?

Input

The input will contain two integers in each line. Each line makes one set of input. These two integers denote the value of v (-100 <= v <= 100) and t(0<=t<= 200) ( t means at the time the particle gains that velocity)

Output

For each line of input print a single integer in one line denoting the displacement in double of that time.

Sample Input

0 0
5 12

Sample Output

0
120

___________________________________________________________________________________

Shahriar Manzoor

水题直接上代码

#include <iostream>
#include <string.h>


using namespace std;

int main(int argc, char *argv[])
{
    //system("color 0a");
    int v,t;
    while( cin>>v>>t )
    {
           cout<<2*v*t<<endl;
    }
    //system("PAUSE");
    return 0;
}