[LintCode]Binary Tree Inorder Traversal
VERSION I Divide & Conquer
/**
* Definition of TreeNode:
* public class TreeNode {
* public int val;
* public TreeNode left, right;
* public TreeNode(int val) {
* this.val = val;
* this.left = this.right = null;
* }
* }
*/
public class Solution {
/**
* @param root: The root of binary tree.
* @return: Inorder in ArrayList which contains node values.
*/
public ArrayList<Integer> inorderTraversal(TreeNode root) {
// 2015-3-22 DFS
ArrayList<Integer> rst = new ArrayList<>();
if (root == null) {
return rst;
}
// divide
ArrayList<Integer> left = inorderTraversal(root.left);
ArrayList<Integer> right = inorderTraversal(root.right);
// conquer
rst.addAll(left);
rst.add(root.val);
rst.addAll(right);
return rst;
}
}
VERSION II Recursion
/**
* Definition of TreeNode:
* public class TreeNode {
* public int val;
* public TreeNode left, right;
* public TreeNode(int val) {
* this.val = val;
* this.left = this.right = null;
* }
* }
*/
public class Solution {
/**
* @param root: The root of binary tree.
* @return: Inorder in ArrayList which contains node values.
*/
public ArrayList<Integer> inorderTraversal(TreeNode root) {
// 2015-4-1 recursion
ArrayList<Integer> rst = new ArrayList<>();
if (root == null) {
return rst;
}
rst.addAll(inorderTraversal(root.left));
rst.add(root.val);
rst.addAll(inorderTraversal(root.right));
return rst;
}
}
本文详细介绍了二叉树中序遍历的两种方法:递归和分治。通过实例演示了如何使用这两种方法实现中序遍历,并解释了每种方法的原理和优缺点。
275





