LeetCode – Remove Duplicates from Sorted Array (Java)

本文介绍了一种在不使用额外空间的情况下去除有序数组中重复元素的方法,并保持每个元素只出现一次。通过一次遍历和两个指针实现了原地修改数组并返回新长度的功能。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

For example,
Given input array A = [1,1,2],

Your function should return length = 2, and A is now [1,2].

Thoughts

The problem is pretty straightforward. It returns the length of array with unique elements, but the original array need to be changed also. This problem should be reviewed with Remove Duplicates from Sorted Array II.

Java Solution

public class Solution {
    public int removeDuplicates(int[] A) {
        if(A.length < 2)
            return A.length;
 
        int j = 0;
        int i = 1;
 
        while(i < A.length){
            if(A[i] == A[j]){
                i++;
            }else{
                A[++j] = A[i++];
            }    
        }
 
        return j+1;
    }
}


评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值