Linux C一站式学习习题答案7.2.1复数

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本文详细介绍了如何在C语言中实现复数的加、减、乘、除运算，并通过自定义函数打印复数，包括实部和虚部的处理。

1、在本节的基础上实现一个打印复数的函数，打印的格式是x+yi，如果实部或虚部为0则省略，例如：1.0、-2.0i、-1.0+2.0i、1.0-2.0i。最后编写一个main函数测试本节的所有代码。想一想这个打印函数应该属于上图中的哪一层？

a.打印函数

#include<stdio.h>

int structa ( double x,double y )
{
    	if ( y==0 )
		printf ( "%.1f\n",x );
	else 
	{
		if (x==0)
			printf ("%.1fi\n",y);
		else
		{
			if ( y>0 )
				printf ("%.1f+%.1fi\n",x,y);
			if ( y<0 )
				printf ("%.1f%.1fi\n",x,y);
		}
	}
	return 0;
}


int main (  )
{
	double x,y;
	printf ("请输入复数的实部和虚部：");
	scanf ("%lf %lf",&x,&y);
	structa ( x,y );
	return 0;
}

转载请注明源地址：http://blog.youkuaiyun.com/whorus1/article/list/2，谢谢！
b.验证函数

#include<stdio.h>
#include<math.h>


double x,y,x1,x2,yy,y2;
struct complex_struct { double x, y; } z,z1,z2;


double real_part(struct complex_struct z)

{
	return z.x;
}



double img_part(struct complex_struct z)

{

	return z.y;

}



double magnitude(struct complex_struct z)

{

	return sqrt(z.x * z.x + z.y * z.y);

}



double angle(struct complex_struct z)

{

	return atan2(z.y, z.x);

}
/****************************************************************************************/


struct complex_struct make_from_real_img(double x, double y)

{

	struct complex_struct z;
	z.x = x;
	z.y = y;
	return z;

}



struct complex_struct make_from_mag_ang(double r, double A)

{

	struct complex_struct z;
	z.x = r * cos(A);
	z.y = r * sin(A);
	return z;
}
/***********************************************************************************************/


struct complex_struct add_complex(struct complex_struct z1, struct complex_struct z2)

{
	return make_from_real_img(real_part(z1) + real_part(z2), img_part(z1) + img_part(z2));
}

struct complex_struct sub_complex(struct complex_struct z1, struct complex_struct z2)

{
	return make_from_real_img(real_part(z1) - real_part(z2), img_part(z1) - img_part(z2));
}

struct complex_struct mul_complex(struct complex_struct z1, struct complex_struct z2)

{
	return make_from_mag_ang(magnitude(z1) * magnitude(z2), angle(z1) + angle(z2));
}

struct complex_struct div_complex(struct complex_struct z1, struct complex_struct z2)

{
	return make_from_mag_ang(magnitude(z1) / magnitude(z2), angle(z1) - angle(z2));
}

int struct_P ( struct complex_struct z )
{
	if ( z.y==0 )
		printf ( "%.1f\n",z.x );
	else 
	{
		if (z.x==0)
			printf ("%.1fi\n",z.y);
		else
		{
			if ( z.y>0 )
				printf ("%.1f+%.1fi\n",z.x,z.y);
			if ( z.y<0 )
				printf ("%.1f%.1fi\n",z.x,z.y);
		}
	}
	return 0;
}

int main (  )
{
	printf ("please enter the parameters of complex:");
	scanf ("%lf%lf%lf%lf",&x1,&yy,&x2,&y2);
	//struct complex_struct z ;
	z1.x = x1;
	z1.y = yy;
	z2.x = x2;
	z2.y = y2;
	printf ( "z1=" );
	struct_P ( z1 );
	printf ( "z2=" );
	struct_P ( z2 );
	printf ( "z1+z2=" );
	z = add_complex( z1,z2 );
	struct_P ( z );
	printf ( "z1-z2=" );
	z = sub_complex( z1,z2 );
	struct_P ( z );
	printf ( "z1*z2=" );
	z = mul_complex( z1,z2 );
	struct_P ( z );
	printf ( "z1/z2=" );
	z = div_complex( z1,z2 );
	struct_P ( z );
	return 0;
}