编写函数squeeze(s1,s2),将字符串s1中任何与字符串s2中字符匹配的字符都删除

//C程序设计语言（第2版）P38 void squeeze(char s1[], char s2[]) { int i, j, k; for (i = k = 0; s1[i] != '/0'; i++) { for (j = 0; s2[j] != '/0' && s2[j] != s1[i]; j++) { ; } if (s2[j] == '/0') { s1[k++] = s1[i]; } } s1[k] = '/0'; }