注:最近这一系列ACM的内容,都是2年多之前的代码,自己回顾一下。
Description
The number S is called the mean of two numbers R1 and R2 if S is equal to (R1+R2)/2. Mirko's birthday present for Slavko was two integers R1 and R2. Slavko promptly calculated their mean which also happened to be an integer but then lost R2! Help Slavko restore R2.
Input
The first and only line of input contains two integers R1 and S, both between -1000 and 1000.
Output
Output R2 on a single line.
Sample Input
11 15
Sample Output
19
Hint
Another Example:
input
4 3
output
2
Source
Croatian Open Competition in Informatics
The number S is called the mean of two numbers R1 and R2 if S is equal to (R1+R2)/2. Mirko's birthday present for Slavko was two integers R1 and R2. Slavko promptly calculated their mean which also happened to be an integer but then lost R2! Help Slavko restore R2.
Input
The first and only line of input contains two integers R1 and S, both between -1000 and 1000.
Output
Output R2 on a single line.
Sample Input
11 15
Sample Output
19
Hint
Another Example:
input
4 3
output
2
Source
Croatian Open Competition in Informatics
简单的模拟题,秒杀级
#include<stdlib.h>
#include<stdio.h>
void main()
{
int R1, S;
scanf("%d %d", &R1, &S);
printf("%d\n", (S * 2 - R1));
//// system("pause");
return 0;
}
本文介绍了一道简单的ACM模拟题,题目要求根据已知数R1和它们的平均数S,求另一个未知数R2。通过给出的C语言代码示例,演示了如何快速解决此类问题。
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