python编写程序计算有多少对质数和

import math
def ss(n):
    i=2
    while(i<=math.sqrt(n)):
        if n%i==0:
            return 0
        i=i+1
    return 1
print("请输入一个整数(小于1000):")
sum=0
m=int(input())
for i in range(2,m):
    if ss(i) and ss(m-i):
        print(i,"+",m-i,"=",m)
        sum+=1
print("有%d对质数的和为%d"%(sum,m))