C语言，用1角2角5角找零的方式

C语言实现用1角2角5角找零

普通方法：

如下图：

实现代码：

#include<stdio.h>

int main()
{
	int x;
	int one, two, five;
	
	scanf("%d", &x);
	
	for ( one = 1; one < x*10; one++) {
		for ( two = 1; two < x*10/2; two++) {
			for ( five =1; five < x*10/5; five++) {
				if ( one + two*2 + five*5 == x*10 ) {
					printf("可以用%d个1角加%d个2角加%d个5角得到%d元\n", one, two , five, x);
				}
			}
		}
	}
	return 0;
}

方法二：

beak接力，满足一种方法即跳出循环

实现如下图：

实现代码：

#include<stdio.h>

int main() 
{
	int x;
	int one, two, five;
	int exit = 0;
	
	scanf("%d", &x);
	for ( one = 1; one < x*10; one++) {
		for ( two = 1; two < x*10/2; two++) {
			for ( five =1; five < x*10/5; five++) {
				if ( one + two*2 + five*5 == x*10 ) {
					printf("可以用%d个1角加%d个2角加%d个5角得到%d元\n", one, two , five, x);
					exit = 1;
					break;
				}
			}
			if ( exit == 1) break;
		}
		if (exit == 1) break;
	}
	return 0;
		
}

方法多样，仅供参考。