Ajax技术
1.使用JQuery中的Ajax实现异步校验
<%@ page contentType="text/html;charset=UTF-8" language="java" %>
<html>
<head>
<title>Title</title>
<script src="${pageContext.request.contextPath}/js/jquery-3.5.1.js"></script>
<script>
function a1() {
$.post({
url:"${pageContext.request.contextPath}/a3",
data:{"name":$("#name").val()},
success:function (data) {
if (data.toString()=="ok"){
$("#userInfo").css("color","green");
}else{
$("#userInfo").css("color","red");
}
$("#userInfo").html(data);
}
})
}
function a2() {
$.post({
url:"${pageContext.request.contextPath}/a3",
data:{"pwd":$("#pwd").val()},
success:function (data) {
if (data.toString()=="ok"){
$("#pwdInfo").css("color","green");
}else{
$("#pwdInfo").css("color","red");
}
$("#pwdInfo").html(data);
}
})
}
</script>
</head>
<p>
用户名:<input type="text" id="name" onblur="a1()">
<span id="userInfo" ></span>
</br>
密码:<input type="password" id="pwd" onblur="a2()">
<span id="pwdInfo" ></span>
</p>
</body>
</html>
@RequestMapping("/a3")
public String a3(String name,String pwd){
String msg="";
if (name!=null){
if("admin".equals(name)){
msg = "ok";
}else{
msg="用户名有误";
}
}
if (pwd!=null){
if("123456".equals(pwd)){
msg = "ok";
}else{
msg="密码有误";
}
}
return msg;
}
2.解决乱码
<mvc:annotation-driven>
<mvc:message-converters>
<bean class="org.springframework.http.converter.StringHttpMessageConverter">
<constructor-arg value="UTF-8"/>
</bean>
<bean class="org.springframework.http.converter.json.MappingJackson2HttpMessageConverter">
<property name="objectMapper">
<bean class="org.springframework.http.converter.json.Jackson2ObjectMapperFactoryBean">
<property name="failOnEmptyBeans" value="false"/>
</bean>
</property>
</bean>
</mvc:message-converters>
</mvc:annotation-driven>