
力扣
力口算法
北海南风
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【力扣】130.被包围的区域(java,深度优先搜索)
提交代码:class Solution { public void solve(char[][] board) { int m = board.length,lines = 0; if(m != 0){ lines = board[0].length; } for (int x = 0; x < m; x++) { dfs(board,x,0).原创 2020-08-18 21:37:03 · 278 阅读 · 1 评论 -
【力扣】695.岛屿的最大面积(java,深度搜索)
提交代码:class Solution { public int maxAreaOfIsland(int[][] grid){ int n = grid.length; int m = grid[0].length; int[] count = new int[1]; int max=0,temp=0; for (int i = 0;i<n;i++){ for (int j = 0;j&.原创 2020-08-18 21:34:40 · 291 阅读 · 1 评论