
法一:优先队列
class Solution {
public:
vector<int> maxSlidingWindow(vector<int>& nums, int k) {
priority_queue<pair<int, int>> q;
for(int i = 0; i < k; ++i){
q.push({nums[i], i});
}
vector<int> res;
res.push_back(q.top().first);
for(int i = k; i < nums.size(); i++){
q.push({nums[i], i});
while(i - q.top().second >= k){
q.pop();
}
res.push_back(q.top().first);
}
return res;
}
};
法二:双端队列
class Solution {
public:
vector<int> maxSlidingWindow(vector<int>& nums, int k) {
deque<int> q;
q.push_back(0);
for(int i = 1; i < k; i++){
while(!q.empty() && nums[i] >= nums[q.back()]){
q.pop_back();
}
q.push_back(i);
}
vector<int> res;
res.push_back(nums[q.front()]);
for(int i = k; i < nums.size(); i++){
while(!q.empty() && nums[i] >= nums[q.back()]){
q.pop_back();
}
q.push_back(i);
while(i - q.front() >= k){
q.pop_front();
}
res.push_back(nums[q.front()]);
}
return res;
}
};