python正则判断一个字符串中是否存在连续序号

python正则判断一个字符串中是否存在连续序号

import re

def has_continuous_numbers(text):
    pattern = r'(\d+)[\.、）)][.\s]*'
    matches = re.findall(pattern, text)
    print(matches)
    if len(matches) > 1:
        numbers = [int(num) for num in matches]
        for i in range(len(numbers) - 1):
            if numbers[i+1] - numbers[i] != 1:
                return False
        return True
    return False

text = "1). 高血压；2). 高血脂；3). 2型糖尿病"
if has_continuous_numbers(text):
    print("字符串中存在连续序号")
else:
    print("字符串中不存在连续序号")