从有序顺序表中删除所有其值重复的元素
题目描述:从有序顺序表中删除所有其值重复的元素,使表中所有元素值均不相同
1.代码如下
#include<stdlib.h>
#include<stdio.h>
#define MaxSize 100
int len,s, t;//输入长度
typedef struct
{
int data[MaxSize];
int length;
}SeqList;
void PrintList(SeqList &L)
{
for (int i = 0; i < L.length; i++)
{
printf("L.data[%d]=%d\n", i, L.data[i]);
}
}
bool Repetition(SeqList &L)
{
if (L.length == 0) return false;
int i = 0,j;
for (i,j = 1; j < L.length; j++)
{
if (L.data[j] != L.data[i])
{
i++;
L.data[i] = L.data[j]; //L.data[i]记录的是一个新的不含重复元素的数组
}
}
L.length = i+1;
return true;
}
void fuzhi(SeqList &L,int len)
{
L.length = len;
for (int i = 0; i < L.length; i++)
{
scanf_s("%d", &L.data[i]);
}
}
int main()
{
SeqList(L);
int len;//输入长度
printf("length=");
scanf_s("%d", &len);
fuzhi(L, len);
Repetition(L);
PrintList(L);
return 0;
}
核心代码写成这样也是可以的
bool Repetition02(SeqList &L)
{
if (L.length == 0) return false;
int i = 0, j;
int count = 0;
for (i, j = 1; j <= L.length; j++) //注意此处为 <=L.length
{
if (L.data[j] != L.data[i])
{
L.data[count] = L.data[i]; //L.data[count]记录的是一个新的不含重复元素的数组
i = j;
count++;
}
}
L.length = count;
return true;
}