1001 A+B Format（C语言）

#include<string.h>

于 2021-03-07 21:37:51 发布

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本文介绍了一段C语言代码，用于计算两个整数之和并以标准格式输出，即把千位以上的数字每三位用逗号隔开。作者分享了如何使用`%03d`格式化输出以及绝对值函数`abs()`的技巧。通过示例和心得，读者可以掌握如何处理不足四位的数字问题。

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1001 A+B Format (20 分)

Calculate a+b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input Specification:

Each input file contains one test case. Each case contains a pair of integers a and b where −10⁶≤a,b≤10⁶
.The numbers are separated by a space.

Output Specification:

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input:

-1000000 9

Sample Output:

-999,991

My code

#include<stdio.h>
#include<stdlib.h>
int main(){
    int a,b,c,d;
    scanf("%d %d",&a,&b);
    c=a+b;
    d=abs(c);
    if(d<1000){printf("%d",c);}
    else if(d<1000000){int m,n;m=c/1000;n=abs(m*1000-c);printf("%d%c%03d",m,',',n);}
    else{int m,n,f;m=c/1000000;n=abs(m*1000-c/1000);f=abs(c-n*1000-m*1000000);printf("%d%c%03d%c%03d",m,',',n,',',f);}
    return 0;
}