weixin_44891121的博客

s = "aabbccacdaaa" count = 1 ans = "" for i in range(1, len(s)): if s[i] == s[i - 1]: count += 1 else: ans += s[i - 1] + str(count) count = 1 ans += s[-1] + str(count) print(s) pr.

n = int(input("请输入数字个数："))m = int(input("请输入移动的位置："))l = []l1 = []for i in range(n): l.append(int(input("Pls input a num:")))print("原数组：",l)if n < m: print("输入有误，移动位置应该小于数字个数")else: for i in range(n-m): l1.append(l.pop())

def inp(n): for i in range(6): n.append(int(input("Pls input a number:"))) print("原数组：", n) for i in range(6): if max(n) == n[i]: n[0], n[i] = n[i], n[0] if min(n) == n[i]: n[-1], n[i] = n[i], .

举例：123反转后为321；-123反转后为-321；10反转后为1def reverse_num(n): str_n = str(n) if str_n[0] == '-': n = -int(str_n[:0:-1]) return n else: n = int(str_n[::-1]) return nn = 10print(reverse_num(n))打印结果1...

l = [1,1,2,3,5,34,23,56,6,6,99]tmp_l = []for i in l: if i not in tmp_l: tmp_l.append(i)print(tmp_l)或者用set()函数l = [1,1,2,3,5,34,23,56,6,6,99]l2 = list(set(l))print(l2)打印结果[1, 2, 3, 5, 34, 23, 56, 6, 99]

def bubble(l): for i in range(len(l)): for j in range(0, len(l) - i - 1): if l[j] > l[j + 1]: l[j], l[j + 1] = l[j + 1], l[j] return ll = [4, 64, 645, 1, 5906, 69]print(bubble(l))打印结果[1, 4, 64, 69, 6.

def num(l): #创建空字典 d = {} #遍历列表 for i in l: #找出列表中int类型的数据 if type(i) is int: if i not in d: d[i] = 1 else: d[i] += 1 return dl = [1, 2, 'abx', 3, 2, 45.