PAT甲级1042

1042 Shuffling Machine （20 分)

Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techniques are seen as weak, and in order to avoid “inside jobs” where employees collaborate with gamblers by performing inadequate shuffles, many casinos employ automatic shuffling machines. Your task is to simulate a shuffling machine.

The machine shuffles a deck of 54 cards according to a given random order and repeats for a given number of times. It is assumed that the initial status of a card deck is in the following order:

S1, S2, …, S13,
H1, H2, …, H13,
C1, C2, …, C13,
D1, D2, …, D13,
J1, J2

where “S” stands for “Spade”, “H” for “Heart”, “C” for “Club”, “D” for “Diamond”, and “J” for “Joker”. A given order is a permutation of distinct integers in [1, 54]. If the number at the i-th position is j, it means to move the card from position i to position j. For example, suppose we only have 5 cards: S3, H5, C1, D13 and J2. Given a shuffling order {4, 2, 5, 3, 1}, the result will be: J2, H5, D13, S3, C1. If we are to repeat the shuffling again, the result will be: C1, H5, S3, J2, D13.
Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer K (≤20) which is the number of repeat times. Then the next line contains the given order. All the numbers in a line are separated by a space.
Output Specification:

For each test case, print the shuffling results in one line. All the cards are separated by a space, and there must be no extra space at the end of the line.
Sample Input:

2
36 52 37 38 3 39 40 53 54 41 11 12 13 42 43 44 2 4 23 24 25 26 27 6 7 8 48 49 50 51 9 10 14 15 16 5 17 18 19 1 20 21 22 28 29 30 31 32 33 34 35 45 46 47

Sample Output:

S7 C11 C10 C12 S1 H7 H8 H9 D8 D9 S11 S12 S13 D10 D11 D12 S3 S4 S6 S10 H1 H2 C13 D2 D3 D4 H6 H3 D13 J1 J2 C1 C2 C3 C4 D1 S5 H5 H11 H12 C6 C7 C8 C9 S2 S8 S9 H10 D5 D6 D7 H4 H13 C5

这次还是两种方法，显然较为麻烦的是我的方法，也就是第二个那个长长的代码块，第一个代码块是我仿照柳神的做法写的，简洁明了，首推，为我们解题提供了一种新的思路，这题首先难到我的是英语单词，我是真的没有读懂什么意思。后来翻了一下晴神宝典知道了题目的意思，感觉需要个pat词典了2333.
这题其实很简单，我觉得考点就在两个数组之间的交换，时间复杂度是2*（54+54）.
然后我觉得需要学习的就是怎么输出S1S2…显然柳神的方法比我的简单一些，具体怎么简单直接看代码吧

char s[6]={"SHCDJ"};
	for(int i=1;i<=54;i++)
	{
		b[i]=b[i]-1;
		cout<<s[b[i]/13]<<b[i]%13+1;
		if(i!=54)
		cout<<" ";
	}

if(c1[54]==53)
	cout<<"J1";
	else if(c1[54]==54)
	cout<<"J2";
	else if(c1[54]>=1&&c1[54]<=13)
	cout<<"S"<<c1[54];
	else if(c1[54]>=14&&c1[54]<=26)
	cout<<"H"<<c1[54]-13;
	else if(c1[54]>=27&&c1[54]<=39)
	cout<<"C"<<c1[54]-26;
	else if(c1[54]>=40&&c1[54]<=52)
	cout<<"D"<<c1[54]-39;

高下立判了。膜就完了，我相信还有别的简单方法，待开发中ing

#include<iostream>
using namespace std;
int main()
{
	int n;
	int a[55],b[55],c[55];
	cin>>n;
	for(int i=1;i<=54;i++)
		cin>>a[i];
	for(int i=1;i<=54;i++){
		b[i]=i;
	}
	for(int i=1;i<=n;i++)
	{	
		for(int k=1;k<=54;k++)
		c[k]=b[k];
		for(int j=1;j<=54;j++)
		b[a[j]]=c[j];
	}
	char s[6]={"SHCDJ"};
	for(int i=1;i<=54;i++)
	{
		b[i]=b[i]-1;
		cout<<s[b[i]/13]<<b[i]%13+1;
		if(i!=54)
		cout<<" ";
	}
	return 0;
}

啰嗦了一大堆，重点还是看代码吧，这些都是我码的，只是参考了一下柳神的思想哦，大体上是一样的。

#include<iostream>
#include<string.h>
using namespace std;
int main()
{
	int n;
	int a[55]={0};
	int c1[55]={0},c2[55]={0};
	cin>>n;
	for(int i=1;i<=54;i++)
		cin>>a[i];
	for(int i=1;i<=54;i++){
		c1[i]=i;
		c2[i]=i;
	}
	for(int i=1;i<=n;i++)
	{
		for(int j=1;j<=54;j++)
		c1[a[j]]=c2[j];
		for(int j=1;j<=54;j++)
		c2[j]=c1[j];
	}
	for(int i=1;i<54;i++)
	{
		if(c1[i]==53)
		cout<<"J1"<<" ";
		else if(c1[i]==54)
		cout<<"J2"<<" ";
		else if(c1[i]>=1&&c1[i]<=13)
		cout<<"S"<<c1[i]<<" ";
		else if(c1[i]>=14&&c1[i]<=26)
		cout<<"H"<<c1[i]-13<<" ";
		else if(c1[i]>=27&&c1[i]<=39)
		cout<<"C"<<c1[i]-26<<" ";
		else if(c1[i]>=40&&c1[i]<=52)
		cout<<"D"<<c1[i]-39<<" ";
	}
	if(c1[54]==53)
	cout<<"J1";
	else if(c1[54]==54)
	cout<<"J2";
	else if(c1[54]>=1&&c1[54]<=13)
	cout<<"S"<<c1[54];
	else if(c1[54]>=14&&c1[54]<=26)
	cout<<"H"<<c1[54]-13;
	else if(c1[54]>=27&&c1[54]<=39)
	cout<<"C"<<c1[54]-26;
	else if(c1[54]>=40&&c1[54]<=52)
	cout<<"D"<<c1[54]-39;
}