题目:有四个数字:1、2、3、4,能组成多少个互不相同且无重复数字的三位数?各是多少?
# -*- coding: UTF-8 -*-
#python3.6.8
count=0
for a in range(1,5):
for b in range(1, 5):
for c in range(1, 5):
if(a!=b and b!=c and a!=c):
print(a,b,c)
count=count+1
print("一共有",count,"个")