1月21日训练赛A

Give you two numbers A and B, if A is equal to B, you should print “YES”, or print “NO”.
Input
each test case contains two numbers A and B.
Output
for each case, if A is equal to B, you should print “YES”, or print “NO”.
Sample Input
1 2
2 2
3 3
4 3
Sample Output
NO
YES
YES
NO

第一个方案

#include <iostream>
#include <cstdio>
using namespace std;
int main()
{
    double a,b;
    while(cin>>a>>b)
    {
        if(a==b)
            cout<<"YES"<<endl;
        else if(a!=b)
            cout<<"NO"<<endl;
    }
}

没有考虑位数和小数点的问题

#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
#define LEN 100000
int main() {
char a[LEN];
char b[LEN];
int lena, lenb, len, i;
while(cin >> a >> b) {
    lena = 0;
    lenb = 0;
    len = strlen(a);
    len--;
    for(i = 0; i <= len; i++) 
    {if(a[i] == '.')
         { lena = i;//a的整数位数
            break;
        }
    }
    while(a[len] == '0' && len > lena && lena != 0)
     {
        a[len] = '\0';
        len--;
    }
    if(a[len] == '.') {
       a[len] = '\0';
    }
    len = strlen(b);
    len--;
    for(i = 0; i <= len; i++) {
        if(b[i] == '.') {
            lenb = i;
            break;
        }
    }
    while(b[len] == '0' && len > lenb && lenb != 0) {
        b[len] = '\0';
        len--;
    }
    if(b[len] == '.') {
        b[len] = '\0';
    }
    if(strcmp(a, b) == 0) {
        cout << "YES" << endl;
    }
    else {
        cout << "NO" << endl;
    }
}
return 0;
}