1108 Finding Average (20 分)
The basic task is simple: given N real numbers, you are supposed to calculate their average. But what makes it complicated is that some of the input numbers might not be legal. A legal input is a real number in [−1000,1000] and is accurate up to no more than 2 decimal places. When you calculate the average, those illegal numbers must not be counted in.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (≤100). Then N numbers are given in the next line, separated by one space.
Output Specification:
For each illegal input number, print in a line ERROR: X is not a legal number
where X
is the input. Then finally print in a line the result: The average of K numbers is Y
where K
is the number of legal inputs and Y
is their average, accurate to 2 decimal places. In case the average cannot be calculated, output Undefined
instead of Y
. In case K
is only 1, output The average of 1 number is Y
instead.
Sample Input 1:
7
5 -3.2 aaa 9999 2.3.4 7.123 2.35
Sample Output 1:
ERROR: aaa is not a legal number
ERROR: 9999 is not a legal number
ERROR: 2.3.4 is not a legal number
ERROR: 7.123 is not a legal number
The average of 3 numbers is 1.38
Sample Input 2:
2
aaa -9999
Sample Output 2:
ERROR: aaa is not a legal number
ERROR: -9999 is not a legal number
The average of 0 numbers is Undefined
题目大意:找出给的数据中合法的数字( [-1000, 1000] ),计算平均值输出,保留两位小数。
思路:读取字符串,判断是不是数字,找全判断条件就可以了。
#include <iostream>
#include <string>
using namespace std;
bool isLegal(string &s, float &num);
bool isChar(char c);
int main()
{
int N, cnt = 0;
float sum = 0;
string s;
scanf("%d", &N);
for (int i = 0; i < N; i++) {
cin >> s;
float num;
if (isLegal(s, num)){
sum += num;
cnt++;
}
else {
printf("ERROR: ");
cout << s;
printf(" is not a legal number\n");
}
}
if (cnt > 1)
printf("The average of %d numbers is %.2f\n", cnt, sum / cnt * 1.0);
else if (cnt == 1)
printf("The average of 1 number is %.2f\n", sum);
else
printf("The average of 0 numbers is Undefined\n");
return 0;
}
bool isLegal(string &s, float &num) {
bool flag = false;
int cnt1 = 0, cnt2 = 0;//分别记录'.'和小数部分的数字数量
if (s[0] == '-')
flag = true;
for (int i = 0; i < s.length(); i++) {
if (flag) {
flag = false;
continue;
}
if (isChar(s[i]) && s[i] != '.')
return false;
else if (s[i] == '.') {
cnt1++;
if (cnt1 > 1)
return false;
}
else if (cnt1 == 1) {
cnt2++;
if (cnt2 > 2)
return false;
}
}
num = stof(s);
return (num >= -1000 && num <= 1000) ? true : false;
}
bool isChar(char c) {
if (c >= '0'&&c <= '9')
return false;
else
return true;
}