LeetCode: 331. Verify Preorder Serialization of a Binary Tree

本文提供了一种不重建树即可验证字符串是否为正确二叉树前序遍历序列化的算法。介绍了如何使用堆栈数据结构来判断由逗号分隔的整数和‘#’字符组成的字符串是否符合二叉树的前序遍历序列化规则。

Question:

Given a string of comma separated values, verify whether it is a correct preorder traversal serialization of a binary tree. Find an algorithm without reconstructing the tree.
Each comma separated value in the string must be either an integer or a character ‘#’ representing null pointer.
You may assume that the input format is always valid, for example it could never contain two consecutive commas such as “1,3”

Solution

public class Solution {
    public boolean isValidSerialization(String preorder) {
    	if (preorder == null || preorder.length() == 0) {
    		return false;
    	}
    	String[] str = preorder.split(",");
    	Stack<String> stack = new Stack<>();
    	for (int i = 0; i < str.length; i++) {
    		String cur = str[i];
    		while (cur.equals("#") && !stack.isEmpty() && stack.peek().equals(cur)) {
    			stack.pop();
    			if (stack.isEmpty()) {
    				return false;
    			}
    			stack.pop();
    		}
    	}
    	return (stack.size() == 1 && stack.peek().equals("#");
    }
}

Note:

用一个#来替换一个数字+两个#, 最后stack里应该只剩下一个#

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