表非常简单
现在求出第二高的分数
思路一:分页
SELECT score FROM tb_score ORDER BY score DESC LIMIT 1,1
此时查询结果是90。如果题目要求去掉重复第一名,则
SELECT DISTINCT score FROM tb_score ORDER BY score DESC LIMIT 1,1
此时查询结果是88,distinct关键字修饰的字段,会把重复的值去掉,此处就是去掉结果是90的。
如果表格为
这时执行
SELECT DISTINCT score FROM tb_score ORDER BY score DESC LIMIT 1,1
查不到结果,
如果题目要求这种情况下显示null,则
SELECT (SELECT DISTINCT score FROM tb_score ORDER BY score DESC LIMIT 1,1) AS secondscore
或者
SELECT IFNULL((SELECT DISTINCT score FROM tb_score ORDER BY score DESC LIMIT 1,1),NULL) AS secondscore
思路二:用max函数
和上面一样,如果题目要求去掉重复的第一名,可以用where比较的方法,求出小于最高分的分数
SELECT MAX(score) FROM tb_score WHERE score < (SELECT MAX(score) FROM tb_score)
如果要求查不到的情况下显示null,则
SELECT (SELECT MAX(score) FROM tb_score WHERE score < (SELECT MAX(score) FROM tb_score)) AS secondscore