python函数参数为n，判定奇偶性求相应算术

def test1(n):
    i = 0
    s = 0.0
    for i in range(2, n + 1, 2):
        s += 1.0 / i
    return s
def test2(n):
    s = 0.0
    for i in range(1, n + 1, 2):
        s += 1 / i
    return s
while True:
    if __name__ == '__main__':
        n = int(input("请输入一个正整数："))
        if n % 2 == 0:
            print(test1(n))
        else:
            print(test2(n))