给定一个数组A[0,1,...,n-1],请构建一个数组B[0,1,...,n-1],其中B中的元素B[i]=A[0]*A[1]*...*A[i-1]*A[i+1]*...*A[n-1]。不能使用除法

class Solution:
    def multiply(self, A):
    # write code here
        if not A:
            return []
        n = len(A)
        B = [None]*n
        B[0]=1
        for i in range(1,n):
            B[i] = B[i-1] * A[i-1]
        temp = 1
        for j in range(n-2,-1,-1):
            temp *= A[j+1]
            B[j] *= temp
        return B