sscanf与正则表达式（c—version）

最新推荐文章于 2025-06-30 10:19:59 发布

原创最新推荐文章于 2025-06-30 10:19:59 发布 · 366 阅读

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本文通过多个示例展示了如何使用C语言中的sscanf函数进行字符串解析，包括跳过数字、匹配特定字符范围及提取指定格式的信息等。

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学习代码：

#include<stdio.h>

void test01();//squeeze numbers
void text02();//squeeze numbers
void test03();//print front[] words
void test04();//match words_1stVersion
void test05();//match words_2stVersion
void test06();//match ^[x1-x2]
void test07();//cut string out using its format
void test08();//take the useful information string
void test09();//practice

int main()
{
    test01();
    test02();
    test03();
    test04();
    test05();
    test06();
    test07();
    test08();
    test09();


    return 0;
}

void test01()
{
    char *ch = "123hello";
    char buf[1024];

    sscanf(ch,"%*d%s", buf);
    printf("1%s",buf);

}

void test02()
{
    char *ch = "hello123";//or add \t or space between o and 1, but not suggested!
    char buf[1024];

    sscanf(ch, "%*[a-z]%s", buf);
    printf("2%s", buf);
}

void test03()
{
    char *ch = "123hello";
    char buf[1024];

    sscanf(ch,"%6s", buf);
    printf("3%s", buf);
}

void test04()
{
    char *ch = "123abcdecccfg";
    char buf[1024];

    sscanf(ch,"%*d%[a-c]", buf);
    printf("4%s", buf);
}

void test05()
{
    char *ch = "aa22bbccdefg123";
    char buf[1024] = {0};

    sscanf(ch, "%[abc]", buf);//if it is not match successfully, then just stop matching
    printf("5%s", buf);
}

void test06()
{
    char *ch = "123abcdefg";
    char buf[1024];

    sscanf(ch,"%[^a-z]", buf);
    printf("6%s", buf);
}

void test07()
{
    char *ch = "219.231.164.200";
    int a, b, c, d;

    a = b = c = d = 0;
    sscanf(ch, "%d.%d.%d.%d", &a, &b, &c, &d);
    printf("7%d %d %d %d", a, b, c, d);
}

void test08()
{
    char *ch = "12345#liuwenhan$1114068569";//take my name
    char buf[1024];

    sscanf(ch,"%*[^#]#%[^$]", buf);
    printf("8%s", buf);
}

void test09()
{
    char *ch = "Helloworld@itcast.cn";
    char buf1[1024];
    char buf2[1024];

    sscanf(ch,"%[^@]", buf1);
    sscanf(ch, "%*[^@]@%s", buf2);
    printf("9%s\n%s", buf1, buf2);
}