CodeForces-118A String Task

原创于 2018-12-07 21:48:20 发布 · 201 阅读

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本文介绍了一个编程初学者Petya在第一堂课上的任务，即编写一个程序处理字符串，包括删除所有元音字母，插入特定字符并在每个辅音前转换大写辅音为小写。文章提供了一个C++实现示例，展示了如何使用循环和条件判断完成任务。

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Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters, it:
deletes all the vowels,
inserts a character “.” before each consonant,
replaces all uppercase consonants with corresponding lowercase ones.
Vowels are letters “A”, “O”, “Y”, “E”, “U”, “I”, and the rest are consonants. The program’s input is exactly one string, it should return the output as a single string, resulting after the program’s processing the initial string.
Help Petya cope with this easy task.

Input

The first line represents input string of Petya’s program. This string only consists of uppercase and lowercase Latin letters and its length is from 1 to 100, inclusive.

Output

Print the resulting string. It is guaranteed that this string is not empty.

Examples

Input
tour
Output
.t.r

Input
Codeforces
Output
.c.d.f.r.c.s

Input
aBAcAba
Output
.b.c.b

题目解析：
先将所有的大写字母转化为小写字母，再利用循环在输出的时候把元音跳过，相当于删除。n是a的长度，本来是用的sizeof(a)，一直都不行，后来才发现无论string里放多长的字符串，它的sizeof()都是固定的，于是就换成了a.size（）。

#include <iostream>
#include <string>
using namespace std;
int main()
{
	string a;
	cin >> a;
	int n;
	n = a.size();
	for (int i = 0; i<n; i++)
	{
		if (a[i] >= 65 && a[i] <= 90)
			a[i] += 32;
		if (a[i] == 97 || a[i] == 101 || a[i] == 105 || a[i] == 111 || a[i] == 117 || a[i] == 121)
			continue;
		else cout << "."<< a[i];
	}
	cout << endl;
}