Random.Next方法 一、重载 Next():返回一个非负随机整数 Random random= new Random(); Console.WriteLine("Generating 10 random numbers:"); for (int ctr = 1; ctr <= 10; ctr++) { int number = random.Next(); Console.WriteLine(number); } Next(Int32):返回一个小于所指定最大值的非负随机整数 Random random= new Random