1001 A+B Format (20分)

最新推荐文章于 2020-09-04 22:24:44 发布

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本文详细介绍了如何使用C++、Python和Java解决A+B问题，并强调了输出格式的重要性，确保数字以标准格式显示，每三位数字用逗号分隔。

A+B Format

Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input Specification:

Each input file contains one test case. Each case contains a pair of integers a and b where −106≤a,b≤106. The numbers are separated by a space.

Output Specification:

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input:

-1000000 9

Sample Output:

-999,991

这道题就是简单的加法运算，注意格式输出就好

C++实现

#include<iostream>
#include<cmath>
using namespace std;
int main(){
	int a, b, c;
	cin >> a >> b;
	c = a+b;
	if(c < 0)    cout << "-";
	c = abs(c);
	string s = to_string(c);
	int t = s.length()%3, t1=0;
	for(int i = 0; i < t; i++)    cout << s[i];
	if(t && s.length()>3)    cout << ",";
	for(int i = t; i < s.length(); i++){
		if(t1%3==0 && t1!=0)    cout << ",";
		cout << s[i];
		t1++;
	}
	return 0;
}

Python实现

 if __name__ == "__main__":
line = input().split(" ")
a, b = int(line[0]), int(line[1])
print('{:,}'.format(a+b))

Java实现

import java.io.BufferedReader;
import java.io.InputStreamReader;
public class Main {
    public static void main(String[] args) throws Exception{
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        String[] line = br.readLine().split(" ");
        br.close();
        int temp = Integer.valueOf(line[0]) + Integer.valueOf(line[1]);
        if(temp < 0){
            System.out.print("-");
        }
        String s = String.valueOf(Math.abs(temp));
        String a = new StringBuffer(s).reverse().toString();
        String get = "";
        for(int i=0;i<a.length();i++){
            get = get + a.charAt(i);
            if((i+1) %3 == 0 && i != a.length() - 1)
                get = get + ',';
        }
        String out = new StringBuffer(get).reverse().toString();
        System.out.print(out);
    }
}