python实现凯撒密码

最新推荐文章于 2024-08-25 22:14:30 发布

原创最新推荐文章于 2024-08-25 22:14:30 发布 · 2.4k 阅读

1 ·

CC 4.0 BY-SA版权

文章标签：

#python

python 专栏收录该内容

1 篇文章

订阅专栏

python实现凯撒密码

刚学习python不久，实现用了比较笨的方法，对我来说很容易理解(><)!

代码如下

str1=list(input())
S=int(input())
Captial=['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W',
'X','Y','Z']
Lowercase=['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v',
'w','x','y','z']
for i in range(len(str1)):
    if str1[i] in Captial:
        num1=Captial.index(str1[i])
        T1=num1+S
        while T1>25:
            T1-=26 
        str1[i]=Captial[T1]
    if str1[i] in Lowercase:
        num2=Lowercase.index(str1[i])
        T2=num2+S
        while T2>25:
            T2-=26
        str1[i]=Lowercase[T2]
for i in range(len(str1)):
    print(str1[i],end="")

第一次写博客，有很多不足的地方，望谅解！