条件语句
1. if基本语句
if 条件:
内部代码块
内部代码块
else:
…
print('....')
if 1 == 1:
print("欢迎进入第一会所1")
print("欢迎进入第一会所2")
# TAB 键
else:
print("欢迎进入一本道")
2. if 支持嵌套
if 1 == 1:
if 2 == 2:
print("欢迎进入第一会所1")
print("欢迎进入第一会所2")
else:
print('欢迎进入东京特')
else:
print("欢迎进入一本道")
3. if elif
inp = input('请输入会员级别:')
if inp == "高级会员":
print('美女')
elif inp == "白金会员":
print('大摩')
elif inp == "铂金会员":
print('一线小明星')
else:
print('城管')
print('开始服务把....')
补充:pass
if 1==1:
pass
else:
print('sb')
3. 条件语句
缩进用4个空格
a.
n1 = input('>>>')
if "alex" == "alex":
n2 = input('>>>')
if n2 == "确认":
print('alex SB')
else:
print('alex DB')
else:
print('error')
注意:
n1 = "alex" 赋值
n1 == 'alex' 比较,
b.
if 条件1:
pass
elif 条件2:
pass
elif 条件3:
pass
else:
pass
print('end')
c. 条件1
and or
if n1 == "alex" or n2 == "alex!23":
print('OK')
else:
print('OK')
PS:
pass 代指空代码,无意义,仅仅用于表示代码块
8. 基本数据类型
字符串(引号):
name = "我是是征文"
name = 'alex'
name = """alex"""
name = '''我是是征文'''
加法:
n1 = "alex"
n2 = "sb"
n4 = "db"
n3 = n1 + n2 + n4
乘法:
n1 = "alex"
n2 = n1 * 10
数字:
age = 13
加减乘除次方余:
a1 = 10
a2 = 20
a3 = a1 + a2
a3 = a1 - a2
a3 = a1 * a2
a3 = 100 / 10
a3 = 4**4
a3 = 39 % 8 # 获取39除以8得到的余数
补充:
a3 = 39 // 8
a = 13
temp = a % 2
if temp == 0:
print("偶数")
else:
print('奇数')
4. 基本数据类型
字符串 - n1 = "alex" n2 = 'root' n3 = """eric""" n4='''tony'''
数字 - age=21 weight = 64 fight = 5
加减乘除等:
字符串:
加法:
n1 = "alex"
n2 = "sb"
n4 = "db"
n3 = n1 + n2 + n4
# "alexsbdb"
乘法:
n1 = "alex"
n3 = n1 * 10
数字:
n1 = 9
n2 = 2
n3 = n1 + n2
n3 = n1 - n2
n3 = n1 * n2
n3 = n1 / n2
n3 = n1 % n2
n3 = n1 ** n2
出题:
11 12 13 ...
num = 12
n = num % 2
if n == 0:
print('偶数')
else:
print('奇数')
5. 循环
死循环
while 1==1:
print('ok')
6. 练习题
if条件语句
while循环
奇数偶数
1、使用while循环输入 1 2 3 4 5 6 8 9 10
n = 1
while n < 11:
if n == 7:
pass
else:
print(n)
n = n + 1
print('----end----')
2、求1-100的所有数的和
n = 1
s = 0
while n < 101:
s = s + n
n = n + 1
print(s)
3、输出 1-100 内的所有奇数
n = 1
while n < 101:
temp = n % 2
if temp == 0:
pass
else:
print(n)
n = n + 1
print('----end----')
4、输出 1-100 内的所有偶数
n = 1
while n < 101:
temp = n % 2
if temp == 0:
print(n)
else:
pass
n = n + 1
print('----end----')
5、求1-2+3-4+5 ... 99的所有数的和
n = 1
s = 0 # s是之前所有数的总和
while n < 100:
temp = n % 2
if temp == 0:
s = s - n
else:
s = s + n
n = n + 1
print(s)