给定一个链表,删除链表的倒数第 n 个节点,并且返回链表的头结点。
示例:
给定一个链表: 1->2->3->4->5, 和 n = 2.
当删除了倒数第二个节点后,链表变为 1->2->3->5
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/remove-nth-node-from-end-of-list
class Solution {
public ListNode removeNthFromEnd(ListNode head, int n) {
ListNode dummy = new ListNode(0);
dummy.next = head;
int length = 0;
ListNode current = head;
while(current != null){
length++;
current = current.next;
}
length -= n;
current = dummy;
while(length > 0){
length--;
current = current.next;
};
current.next = current.next.next;
return dummy.next;
}
}
class Solution {
public ListNode removeNthFromEnd(ListNode head, int n) {
ListNode dummy = new ListNode(0);
dummy.next = head;
ListNode fast = dummy.next;
ListNode slow = dummy ;
for(int i=0;i<n;i++){
fast = fast.next;
}
while(fast != null){
fast = fast.next;
slow = slow.next;
}
slow.next = slow.next.next;
return dummy.next;
}
}