show databases;
show variables like '%char%';-- 创建数据库的sql
create database if not exists study charset =utf8;
use develop;
show tables;-- 删除数据库的sql
drop database if exists develop;-- 创建一个用户
create user 'develop'@'%' identified by 'sa';-- 删除一个用户
drop user 'develop'@'%';-- 给develop用户赋予对develop数据的所有表的权限
grant all privileges on develop.* to 'develop'@'%' identified by 'sa';
insert into mysql.user(Host,User,Password,ssl_cipher, x509_issuer,x509_subject)values('%','develop',password('sa'),'','','');
update mysql.user set Password=Password('1') where user ='develop' and host ='%';
select host,user, Password from mysql.user;
delete from mysql.user where user ='develop' and host ='%';
use study;-- 创建表
create table student(
sno int,
name varchar(10),
age int,
sex char(1));-- 删除表
drop table student;-- 创建带有自增主键的表
create table student(
id int unsigned auto_increment,
name varchar(10),
age int,
gender char(1),
primary key (id));-- 添加classname字段
alter table study.student
add (
classname varchar(100));-- 修改gender列的长度
alter table study.student
modify gender char(2);-- 修改gender列为sex,长度增加为10
alter table study.student
change gender sex char(10);-- 删除列
alter table study.student
drop classname;-- 修改表名
alter table study.student
rename to stu;
show create table stu;-- 在stu表中插入一个学生记录
insert into stu(name, age, sex)values('zhangsan',20,'male');
select * from stu;
insert into stu(name)values('lisi');
insert into stu(id, name)values(3,'xiaoer');
insert into stu(id, name)values(3,'xiaoming');
insert into stu(sex, name, age, id)values('male','xiaohong',3,4);-- 在stu表中插入行的另外一种写法
-- 不建议使用此方式:1) 列不明确。2)当表有新增的列时,会产生毁灭性的bug
insert into stu values (5,'wangwu',20,'male');
alter table stu modify name varchar(20);-- 通过update语句修改记录
update stu set name='zhangsansan', age =25 where id =1;-- between 条件
update stu set age = age +1 where age between 10 and 20;-- 上机练习
-- 创建一个学生表:
create table student(
id char(6),
name varchar(50),
age int,
gender varchar(50),
tag varchar(2));-- 插入测试数据
INSERT INTO student VALUES('S_1001','liuYi',35,'male','');
INSERT INTO student VALUES('S_1002','chenEr',15,'female','');
INSERT INTO student VALUES('S_1003','zhangSan',95,'male','');
INSERT INTO student VALUES('S_1004','liSi',65,'female','');
INSERT INTO student VALUES('S_1005','wangWu',55,'male','');
INSERT INTO student VALUES('S_1006','zhaoLiu',75,'female','');--1. 将为'S_1003'的学生的年龄改为25
update study.student set age =25 where id ='S_1003';--2. 将'wangwu'的性别改成NULL
update study.student set gender = null where name ='wangWu' or id ='S_1005';--3. 将年龄大于等于35岁的人标记成'1'
update study.student set tag ='1' where age >=35;--4. 将年龄大于等于15岁小于35岁的人标记成'0'
update study.student set tag ='0' where age >=15 and age <35;-- 删除语句
delete from study.student where id ='S_1001' and gender ='famale';
delete from study.student;-- 截断:清空student表的所有数据,无法恢复
truncate table student;-- 查询示例
-- 创建员工表
CREATE TABLE emp(
empno INT,/*员工编号*/
ename VARCHAR(50),/*员工名称*/
job VARCHAR(50),/*工作职位*/
mgr INT,/*管理编号*/
hiredate DATE,/*入职时间*/
sal DECIMAL(7,2),/**薪酬/
comm decimal(7,2),/*奖金*/
deptno INT/*部门编号*/);
drop table dept;
alter table dept default character set utf8;/*修改表编码格式为utf8*/
alter table dept convert to character set utf8;/*修改列属性的格式为utf8*/
SHOW FULL COLUMNS FROM dept;/*查看dept表的编码格式*/-- 创建部门表
CREATE TABLE dept(
deptno INT ,/*部门编号*/
dname varchar(40),/*部门名称*/
loc varchar(40)/*工作地*/);-- 插入员工表测试数据
INSERT INTO emp VALUES (1009,'zenganiu','chairman', NULL,'2001-11-17',50000, NULL,10);
INSERT INTO emp VALUES (1004,'liubei','manager',1009,'2001-04-02',29750, NULL,20);
INSERT INTO emp VALUES (1006,'guanyu','manager',1009,'2001-05-01',28500, NULL,30);
INSERT INTO emp VALUES (1007,'zhangfei','manager',1009,'2001-09-01',24500, NULL,10);
INSERT INTO emp VALUES (1008,'zhugeliang','analyst',1004,'2007-04-19',30000, NULL,20);
INSERT INTO emp VALUES (1013,'pangtong','analyst',1004,'2001-12-03',30000, NULL,20);
INSERT INTO emp VALUES (1002,'daiyisi','salesman',1006,'2001-02-20',16000,3000,30);
INSERT INTO emp VALUES (1003,'yintianzheng','salesman',1006,'2001-02-22',12500,5000,30);
INSERT INTO emp VALUES (1005,'xiexun','salesman',1006,'2001-09-28',12500,14000,30);
INSERT INTO emp VALUES (1010,'weiyixiao','salesman',1006,'2001-09-08',15000,0,30);
INSERT INTO emp VALUES (1012,'chengpu','clerk',1006,'2001-12-03',9500, NULL,30);
INSERT INTO emp VALUES (1014,'huanggai','clerk',1007,'2002-01-23',13000, NULL,10);
INSERT INTO emp VALUES (1011,'zhoutai','clerk',1008,'2007-05-23',11000, NULL,20);
INSERT INTO emp VALUES (1001,'ganning','clerk',1013,'2000-12-17',8000, NULL,20);-- 插入部门表测试数据
INSERT INTO dept (deptno,dname,loc)VALUES (10,'企划部','北京');
INSERT INTO dept (deptno,dname,loc)VALUES (20,'公关部','上海');
INSERT INTO dept (deptno,dname,loc)VALUES (30,'销售部','广州');
INSERT INTO dept (deptno,dname,loc)VALUES (40,'财务部','武汉');-- 基础查询
select * from emp;-- 指定列查询
select empno, ename from emp;-- distinct 对查询出的记录去重
select distinct job from emp;
select distinct deptno from emp;
select distinct job, deptno from emp;-- 列运算
select *, sal *1.5 from emp;
select *, sal + comm from emp;-- null值转换函数:ifnull(field, value)
select *, sal +IFNULL(comm,0) from emp;
select empno,ename,job,ifnull(mgr,'boss'),hiredate,sal,comm,deptno from emp;-- 字符串连接
select concat('$', sal) from emp;
select concat(ename, job) from emp;
select concat('my name is ', ename,' my job is ', job) from emp;-- 给列起别名
select concat('my name is ', ename,' my job is ', job) as name_job from emp;
select *, sal +IFNULL(comm,0) as 奖金 from emp;
select ename as 姓名 from emp;-- 条件查询
select empno,ename,sal,comm from emp where sal >10000 and comm is not null;
select empno,ename,sal,comm from emp where sal between 20000 and 30000;
select empno,ename,sal,comm from emp where job in ('chairman','manager');-- 模糊查询
SELECT * FROM emp WHERE ename LIKE 'z_______';
select * from emp where ename like '______';
select * from emp where ename like 'z%';
select * from emp where ename like '%z%';
select * from emp where ename like '_h%';
select * from emp where ename like '%n_';
use Student;-- 排序,升序和降序,默认是升序,asc升序,desc降序
select * from emp order by empno;
select * from emp order by empno asc;
select * from emp order by empno desc;-----复合函数
------count函数
select count(*)from emp;
select count(comm)from emp;
select count(*)from emp where sal >25000;
select count(*)from emp where sal +ifnull(comm)>25000;
select count(comm),count(mgr)from emp ;/*sum函数*/
select sum(sal) from emp;
select sum(sal),sum(comm) from emp;
select sum(sal)+ifnull(comm,0)from emp;
select sum(sal)/count(*)from emp;
select sum(ename) from emp;-------avg函数
select avg(sal)from emp;
select avg(ename)from emp;---------max函数
select max(sal)from emp;
select max(ename)from emp;
select max(comm)from emp;----------- min 函数
select min(sal)from emp;
select min(ename)from emp;
select min(comm)from emp;-----------------union 函数
select max(sal)from emp;
union
select min(sal) from emp;
select sum(sal),sum(comm)from emp;
union
select max(sal) from emp;
select * from emp;
union
select * from emp;
select * from emp;
union all
select * from emp;-----分组查询 group by
select deptno,count(*) from emp group by deptno;
select job ,count(*) from emp group by deptno;
select job ,sum(sal) from emp group by job;
select job ,sum(sal),avg(sal),max(sal),min(sal)from emp group by job;---------------组条件
-----------------分组前条件
select deptno ,count(*)from emp where sal>15000 group by deptno;----------------分组后条件
select deptno ,count(*)from emp group by deptno having count(*)>3;
select deptno ,sum(sal) from emp group by deptno having count(*)>3;------分组后排序
select deptno ,count(*)from emp where sal>15000 group by deptno having count(*)>1 order by deptno desc ;/*第五条数据开始,往后查4条数据*/
select * from emp order by empno limit 5,4;/*分页查询*/
select *from emp order by empno limit 5;
select *from emp order by empno limit 0,5;/*从0开始,包括第一行,到第一行*//*一页5条,查询第三页的数据*/
select *from emp order by empno limit 10,5;
select * from emp order by empno limit 10,5;/*
1、查询出部门编号为30的员工
2、查询出所有销售员的姓名、编号和部门编号
3、找出奖金高于工资的员工
4、找出奖金高于工资30%的员工
5、找出部门编号为10的所有经理,和部门编号为20中所有销售员的详细资料
*/
select * from emp where deptno=30;
select ename,empno,deptno from emp where job='salesman';
select * from emp where comm>sal;
select * from emp where comm>sal *0.30;
select * from emp where deptno =10 and job='manager'1、找出部门编号为10中的所有经理,部门编号为20中所有销售员,还有即不是经理也不是销售员但其工资大或大于或等于20000的所有员工详细资料。
select * from emp where deptno='10'and job='manager'
union
select * from emp where deptno ='20'and job='salesman'
union
select *from emp where (job<>'manager'or job <>'salesman')and sal >=200000;2、无奖金或者奖金低于1000的员工
select *from emp where comm is null or comm<1000;------3、查询名字由8个字符组成的员工
select *from emp where ename like '________';4、查询2000年入职的员工
select *from emp where year(hiredate)=2000;5查询所有员工的详细信息,用编号升序排序。
select *from emp order by empno ;
use Student
-- 插入部门表测试数据
INSERT INTO dept VALUES (10,'企划部','北京');
INSERT INTO dept VALUES (20,'公关部','上海');
INSERT INTO dept VALUES (30,'销售部','广州');
INSERT INTO dept VALUES (40,'财务部','武汉');
INSERT INTO dept VALUES (10,'企划部','北京');
INSERT INTO dept VALUES (20,'公关部','上海');
INSERT INTO dept VALUES (30,'销售部','广州');
INSERT INTO dept VALUES (40,'财务部','武汉');/*我们要取出员工工号,姓名、部门名称 、入职时间、等信息;该如何取*/
select emp.empno , emp.ename, dept.dname,emp.hiredate from emp inner join dept on emp.deptno=dept.deptno;
等价于
select emp.empno,emp.ename,dept.dname,emp.hiredate from emp, dept where emp.deptno=dept.deptno;
select *from emp order by empno ;
show full columns from dept;------left join
select empno,ename,dname,hiredate from emp left join dept on emp.deptno =dept.deptno;------ right join
select empno ,ename,dname,hiredate from emp right join dept on emp.deptno =dept.deptno;----子查询:在另一条是 select 作为条件
select *from emp where deptno in (select deptno from dept where loc='北京');
select *from emp where not exists(select deptno from dept where loc='北京'and dept.deptno=emp.deptno);------1、查询出部门内所有员工薪酬低于20000的员工的部门名称及位置;
select dname ,loc from dept where deptno in(select deptno from emp where sal<20000);
select dname ,loc from dept where deptno in(select deptno from emp group by emp.deptno having max(sal)<20000);2、查询‘武汉’地区所有员工的工作(job);
select job from emp where deptno in (select deptno from dept where loc='武汉');3、查询所有job 不为‘chairman’的员工的工号、姓名、部门名称和办公地址;
select empno,ename ,dname,loc from emp left join dept on emp.deptno =dept.deptno where job <>'chairman';===更高效的写法
select empno,ename ,dname,loc from emp left join dept on emp.deptno =dept.deptno where not exists(select 1 from emp e where e.empno=emp.empno and job ='chairman');