笔记本

dydt+μy=cλyα(0<α<1)\frac{d y}{d t}+\mu y=c \lambda y^{\alpha}(0<\alpha<1)dtdy​+μy=cλyα(0<α<1)dydt+μy=f0λyα\frac{\mathrm{d} y}{\mathrm{d} t}+\mu y=f_{0} \lambda y^{\alpha}dtdy​+μy=f0...

dydt+μy=cλyα\frac{d y}{d t}+\mu y=c \lambda y^{\alpha}dtdy​+μy=cλyα解析解：y(t)={cλμ[1−(1−μK0K˙0)e−(1−α)μt]}11−αy(t)=\left\{\frac{c \lambda}{\mu}\left[1-\left(1-\mu \frac{K_{0}}{\dot{K}_{0}}\right) e^{-...