ZOJ 3961-Let's Chat

ACM即时通讯软件新增好友分数功能,若A和B连续m天互发消息,他们之间的好友分数加1。输入包含多组测试用例,每组给出天数n,连续天数m,以及A到B和B到A的消息记录,求n天后的好友分数。样例中,A和B在第1、2、3、5、6、7、8、10天互发消息,m=3,因此在第3、7、8天分数+1,答案为3。

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ACM (ACMers' Chatting Messenger) is a famous instant messaging software developed by Marjar Technology Company. To attract more users, Edward, the boss of Marjar Company, has recently added a new feature to the software. The new feature can be described as follows:

If two users, A and B, have been sending messages to each other on the last m consecutive days, the "friendship point" between them will be increased by 1 point.

More formally, if user A sent messages to user B on each day between the (i - m + 1)-th day and the i-th day (both inclusive), and user B also sent messages to user A on each day between the (i - m + 1)-th day and the i-th day (also both inclusive), the "friendship point" between A and B will be increased by 1 at the end of the i-th day.

Given the chatting logs of two users A and B during n consecutive days, what's the number of the friendship points between them at the end of the n-th day (given that the initial friendship point between them is 0)?

Input

There are multiple test cases. The first line of input contains an integer T (1 ≤ T ≤ 10), indicating the number of test cases. For each test case:

The first line contains 4 integers n (1 ≤ n ≤ 109), m (1 ≤ m ≤ n), x and y (1 ≤ x, y ≤ 100). The meanings of n and m are described above, while x indicates the number of chatting logs about the messages sent by A to B, and y indicates the number of chatting logs about the messages sent by B to A.

For the following x lines, the i-th line contains 2 integers la, i and ra, i (1 ≤ la, i ≤ ra, i ≤ n), indicating that A sent messages to B on each day between the la, i-th day and the ra, i-th day (both inclusive).

For the following y lines, the i-th line contains 2 integers lb, i and rb, i (1 ≤ lb, i ≤ rb, i ≤ n), indicating that B sent messages to A on each day between the lb, i-th day and the rb, i-th day (both inclusive).

It is guaranteed that for all 1 ≤ i < x, ra, i + 1 < la, i + 1 and for all 1 ≤ i < y, rb, i + 1 < lb, i + 1.

Output

For each test case, output one line containing one integer, indicating the number of friendship points between A and B at the end of the n-th day.

Sample Input

2
10 3 3 2
1 3
5 8
10 10
1 8
10 10
5 3 1 1
1 2
4 5

Sample Output

3
0

Hint

For the first test case, user A and user B send messages to each other on the 1st, 2nd, 3rd, 5th, 6th, 7th, 8th and 10th day. As m = 3, the friendship points between them will be increased by 1 at the end of the 3rd, 7th and 8th day. So the answer is 3.

#include <iostream>
using namespace std;

struct Chat{
    int f;
    int r;
};

Chat a[101],b[101];
int main(){
    int t;
    int n,m,x,y,ans;

    cin >> t;
    while(t--){
        ans = 0;
        cin >> n >> m >> x >> y;
        for(int i = 0;i < x;i++){
            cin >> a[i].f >> a[i].r;
        }
        for(int i = 0;i < y;i++){
            cin >> b[i].f >> b[i].r;
        }
        for(int i = 0;i < x;i++){
            for(int j = 0;j < y;j++){
                int f = max(a[i].f,b[j].f);
                int r = min(a[i].r,b[j].r);
                if(r-f>=m-1) ans+=(r-f-m+2);
            }
        }
        cout << ans << endl;
    }
}

 

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