python对这两种语句执行的工作几乎没有区别:>>> import dis
>>> def inplace_add():
... a = 0
... a += 1
...
>>> def add_and_assign():
... a = 0
... a = a + 1
...
>>> dis.dis(inplace_add)
2 0 LOAD_CONST 1 (0)
3 STORE_FAST 0 (a)
3 6 LOAD_FAST 0 (a)
9 LOAD_CONST 2 (1)
12 INPLACE_ADD
13 STORE_FAST 0 (a)
16 LOAD_CONST 0 (None)
19 RETURN_VALUE
>>> dis.dis(add_and_assign)
2 0 LOAD_CONST 1 (0)
3 STORE_FAST 0 (a)
3 6 LOAD_FAST 0 (a)
9 LOAD_CONST 2 (1)
12 BINARY_ADD
13 STORE_FAST 0 (a)
16 LOAD_CONST 0 (None)
19 RETURN_VALUE
区别在于aINPLACE_ADD与aBINARY_ADD。
结果计时太接近,无法调用哪一个更快:>>> import timeit
>>> timeit.timeit('inplace_add', 'from __main__ import inplace_add', number=10000000)
0.32667088508605957
>>> timeit.timeit('add_and_assign', 'from __main__ import add_and_assign', number=10000000)
0.34172606468200684
所以,在python中,差别可以忽略不计。别担心。