基本过程:假设一序列为R[0]~R[n-1],第一次用R[0]和R[1]~R[n-1]相比较,若小于R[0],则交换至R[0]位置上。第二次从R[1]~R[n-1]中选取最小值,与R[1]交换,....,第i次从R[i-1]~R[n-1]中选取最小值,与R[i-1]交换,.....,第n-1次从R[n-2]~R[n-1]中选取最小值,与R[n-2]交换,总共通过n-1次,得到一个按排序码从小到大排列的有序序列。
代码实现:
package paixu;
import java.util.Arrays;
public class Kuai {
public static void main(String[] args) {
int[] a = {6,7,78,26,79,99,26,45,32,12,52,22,11,33};
System.out.println("排序前:" + Arrays.toString(a));
//直接选择排序
int temp = 0;
for (int i = 0; i < a.length-1; i++) {//外层循环控制循环行数
temp = i;
for (int j = i+1; j < a.length; j++) {//内层循环控制循环列数
if(a[temp]>a[j]) {
temp = j;
}
}
int t;
t = a[i];
a[i] = a[temp];
a[temp] = t;
}
System.out.println("排序后:" + Arrays.toString(a));
}
运行结果如下:
排序前:[6, 7, 78, 26, 79, 99, 26, 45, 32, 12, 52, 22, 11, 33]
排序后:[6, 7, 11, 12, 22, 26, 26, 32, 33, 45, 52, 78, 79, 99]