select (year(date1)-year(date2))*12+(month(date1)-month(date2)) as month_num f
hive中获取两个事件的月份差
最新推荐文章于 2024-08-28 04:18:08 发布
select (year(date1)-year(date2))*12+(month(date1)-month(date2)) as month_num f
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