日历查询系统c语言1,使用C语言编写日历查询，要求输入年份，显示日历按两列输出...

匿名用户

1级

2014-05-24 回答

#include <stdio.h>

long int f(int year,int month)

{

if(month<3) return year-1;

else return year;

}

long int g(int month)

{

if(month<3) return month+13;

else return month+1;

}

long int n(int year,int month,int day)

{

return 1461L*f(year,month)/4+153L*g(month)/5+day;

}

int w(int year,int month,int day)

{

return(int) ((n(year,month,day)%7-621049L%7+7)%7);

}

int date[12][6][7];

int day_tbl[ ][12]={{31,28,31,30,31,30,31,31,30,31,30,31},{31,29,31,30,31,30,31,31,30,31,30,31}};

main()

{

int sw,leap,i,j,k,wd,day;

int year;

char title[]="SUM MON TUE WED THU FRI SAT";

printf("Please input the year whose calendar you want to know:\n");

scanf("%d%*c",&year);

sw=w(year,1,1);

leap=year%4==0&&year%100||year%400==0;

for(i=0;i<12;i++)

for(j=0;j<6;j++)

for(k=0;k<7;k++)

date[i][j][k]=0;

for(i=0;i<12;i++)

for(wd=0,day=1;day<=day_tbl[leap][i];day++)

{

date[i][wd][sw]=day;

sw=++sw%7;

if(sw==0) wd++;

}

printf("\n|================== The Calendar of Year %d==================|\n|",year);

for(i=0;i<6;i++)

{

for(wd=0,k=0;k<7;k++)

wd+=date[i][5][k]+date[i+6][5][k];

wd=wd?6:5;

printf(" %2d %s %2d %s|\n|",i+1,title,i+7,title);

for(j=0;j<wd;j++)

{

printf(" ");

for(k=0;k<7;k++)

if(date[i][j][k])

printf("%4d",date[i][j][k]);

else printf(" ");

printf(" ");

for(k=0;k<7;k++)

if(date[i+6][j][k])

printf("%4d",date[i+6][j][k]);

else printf(" ");

printf("|\n|");

}

}

puts("==============================================================|");

}

这是我们当初的作业，不知合适不