Mysql语言select嵌套语句_在MySQL中嵌套多个SELECT语句的正确方法是什么?

在尝试执行一个复杂的SQL查询时,遇到了一个错误:'Unknown column 'distance' in 'where clause'。查询涉及到地点(locations)表及其关联表的数据聚合,包括投票数、评分、查看数、程序数以及计算与特定经纬度的距离。错误表明'distance'列在查询中未被定义。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

我有以下查询:

SELECT

locations.*,

(SELECT COUNT(id) FROM location_scores WHERE location_id = locations.id) AS total_votes,

(SELECT AVG(location_score) FROM location_scores WHERE location_id = locations.id) AS rating,

(SELECT COUNT(id) FROM location_views WHERE location_id = locations.id) AS total_views,

(SELECT COUNT(id) FROM location_procedures WHERE location_id = locations.id) AS total_procedures,

(SELECT ((ACOS(SIN(32.9063840 * PI() / 180) * SIN(location_latitude * PI() / 180) + COS(32.9063840 * PI() / 180) * COS(location_latitude * PI() / 180) * COS((-96.8590890 - location_longitude) * PI() / 180)) * 180 / PI()) * 60 * 1.1515) FROM locations) AS distance

FROM locations

WHERE distance <= '5'

AND locations.id IN ('57', '57', '57', '57', '57', '57', '57', '57', '57', '57', '68', '68', '70', '73', '73', '76', '76', '76', '76', '76', '77', '77')我不断收到以下错误:

Unknown column distance in where clause

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值