此问题的关键在于怎么存放待计算的数据(包括计算过程中的中间结果)以及怎样从输入字符串中分解出运算符和数据。
C语言版本:
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
typedef struct Node {
double Data[1000];
int top;
}*Stack;
double Calculate(double a, double b, char c) {
switch (c) {
case '+': return a + b;
case '-':return a - b;
case '*':return a * b;
case'/':return a / b;
}
}
void Push(Stack S, double a) {
S->Data[++S->top] = a;
}
double Pop(Stack S) {
return S->Data[S->top--];
}
int IsEmpty(Stack S) {
if (S->top == -1) return 1;
return 0;
}
int main() {
char s[1000];
int len,i;
double a, b, res;
fgets(s, 1000,stdin);
Stack S;
S = (Stack)malloc(sizeof(struct Node));
S->top = -1;
len = strlen(s);
for (i = len - 1; i >= 0; i--) {
if (((s[i] - '0') >= 0) && ((s[i] - '0') <= 9)) {
a = s[i] - '0';
i--;
while (s[i] != ' '&&i >= 0) {
a = 10 * (s[i] - '0') + a;
i--;
}
Push(S, a);
}
else if (s[i] == '+' || s[i] == '-' || s[i] == '*' || s[i] == '/') {
if (!IsEmpty(S)) {
a = Pop(S);
}
else {
printf("ERROR\n");
return 0;
}
if (!IsEmpty(S)) b = Pop(S);
else {
printf("ERROR\n");
return 0;
}
if (s[i] == '/'&&b == 0) {
printf("ERROR\n");
return 0;
}
res = Calculate(a, b, s[i]);
Push(S, res);
}
}
printf("%.1f", res);
return 0;
}