给定一棵二叉树,想象自己站在它的右侧,按照从顶部到底部的顺序,返回从右侧所能看到的节点值。
示例:
输入: [1,2,3,null,5,null,4]
输出: [1, 3, 4]
解释:
1 <---
/ \
2 3 <---
\ \
5 4 <---
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/binary-tree-right-side-view
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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> rightSideView(TreeNode* root)
{
vector<int> ret;
//vector<vector<int>> result;
if (root == NULL) {
return ret;
}
queue<TreeNode *> Q;
Q.push(root);
while (!Q.empty()) {
int size = Q.size();
//vector<int> level;
for (int i = 0; i < size; i++) {
TreeNode *head = Q.front(); Q.pop();
if(i == size -1)
ret.push_back(head->val);
//level.push_back(head->val);
if (head->left != NULL) {
Q.push(head->left);
}
if (head->right != NULL) {
Q.push(head->right);
}
}
//result.push_back(level);
}
return ret;
}
};