bool isMatch(const char *s, const char *p) {
const char* star=NULL;
const char* ss=s;
while (*s){
//advancing both pointers when (both characters match) or ('?' found in pattern)
//note that *p will not advance beyond its length
if ((*p=='?')||(*p==*s)){s++;p++;continue;}
// * found in pattern, track index of *, only advancing pattern pointer
if (*p=='*'){star=p++; ss=s;continue;}
//current characters didn't match, last pattern pointer was *, current pattern pointer is not *
//only advancing pattern pointer
if (star){ p = star+1; s=++ss;continue;}
//current pattern pointer is not star, last patter pointer was not *
//characters do not match
return false;
}
//check for remaining characters in pattern
while (*p=='*'){p++;}
return !*p;
}
通配符匹配---------很棒的思路
最新推荐文章于 2025-10-07 08:30:00 发布
本文介绍了一种实现正则表达式匹配的算法。该算法能够处理包括'*'和'?'在内的特殊字符,并通过指针操作高效地进行字符串与模式的匹配。文中详细解释了不同情况下指针的移动逻辑,包括遇到'*'时的状态转移处理。

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