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leetcode 28 :strStr
class Solution { public int strStr(String haystack, String needle) { if(needle == null || needle.length() <= 0){ return 0; } int hlen = haystack.length(); int nlen = needle.length(); if(hlen < .原创 2020-05-28 18:27:52 · 112 阅读 · 0 评论 -
HDU -1001 Exponentiation(Java)
ExponentiationTime Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 2798 Accepted Submission(s): 761 Problem DescriptionProblems involving the computatio...原创 2018-07-03 20:29:44 · 222 阅读 · 0 评论 -
HDU-1002 A + B Problem II
A + B Problem IITime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4112 Accepted Submission(s): 1434 Problem DescriptionI have a very simple problem f...原创 2018-07-02 22:24:37 · 118 阅读 · 0 评论 -
替换空格--牛客剑指offer2
题目描述请实现一个函数,将一个字符串中的空格替换成“%20”。例如,当字符串为We Are Happy.则经过替换之后的字符串为We%20Are%20Happy。需要注意的是:传的是 StringBuffer 类型的字符串;代码如下:public String replaceSpace(StringBuffer str) { for(int i=0;i<str.length();i++...原创 2018-06-29 00:11:15 · 138 阅读 · 0 评论