21. Merge Two Sorted Lists
题目描述
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Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
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Example:
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Input: 1->2->4, 1->3->4
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Output: 1->1->2->3->4->4
代码
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) {
ListNode head(0); //这里还是不是很清楚为什么声明为指针的会出错。
ListNode* cur;
cur = &head;
while(l1 != nullptr || l2 != nullptr)
{
if(!l1)
{
cur->next = l2;
break;
}
if(!l2)
{
cur->next = l1;
break;
}
if(l1->val <= l2->val)
{
cur->next = l1;
l1 = l1->next;
}
else
{
cur->next = l2;
l2 = l2->next;
}
cur=cur->next;
}
return head.next;
}
};