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二分搜索最大值，接下来询问，求下两两差的gcd及可 #include<bits/stdc++.h> using namespace std; #define fst first #define sec second #define sci(num) scanf("%d",&num) #define scl(num) scanf("%lld",&n

枚举Mi，算对应的P，取最大概率大于1-P #include<bits/stdc++.h> using namespace std; #define sci(num) scanf("%d",&num) #define scl(num) scanf("%lld",&num) #define mem(a,b) memset(a,b,sizeof a)