ajax提交form表单

<button type="submit" class="am-btn am-btn-primary" onclick="submitForm('/goods/savaAdd')">保存</button>

function submitForm(url) {

    //获取当前的表单
    var form = new FormData(this)
    $.ajax({
            type: "POST",
            url: url,
            async: true,

	    //.serialize()序列化表单数据
            data: $("#adgdform").serialize(),
            success:
                function (responseText) {
                    $("#con").html(responseText)
                }
            , error: function () {
                alert("跳转失败");
            }
        }
    )
}