Scipy插值估计

问题

已知：
sin(0.32)=0.314567
sin(0.34)=0.333487
sin(0.36)=0.352274
问：
用线性插值法及抛物线插值法（二次插值）求sin(0.3367)

代码

#-*-coding:utf-8 -*-
from scipy import interpolate #导入内插方式
from numpy import sin
x=[0.32,0.34,0.36]
y=[0.314567,0.333487,0.352274]
x3=0.3367
for kind in ["linear","quadratic"]:	
	f=interpolate.interp1d(x,y,kind=kind)
	y3=f(x3)
	print(kind,"插值法%.6f" %y3)

结果

linear 插值法0.330365
quadratic 插值法0.330374