python实现斐波纳挈数列

0,1,1,2,3,5,8,…像这样的数列，输出前10个

class Fib(object):
    def __call__(self,num):
        a,b,L=0,1,[]
        for n in range(num):
            L.append(a)
            a,b=b,a+b
        return L

f = Fib()
print f(10)

[0, 1, 1, 2, 3, 5, 8, 13, 21, 34]