算法题 (使用python 处理)

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博客记录了作者在LeetCode做的算法题，题目是给定一个整数数组，找出数组中两个数的索引，使它们的和等于特定目标值，且假设每个输入只有一个解，同一个元素不能使用两次，并给出了示例。

记录自己leetCode做的算法题

1、Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the sameelement twice.

Example:

Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].

def towSum(nums,target):
    indice=0
    flag=True
    while flag:
        length = len(nums)
        if length>1:
           a=nums.pop(0)
           indice += 1
        if length==1:
            print('无法计算得出target' %target)
            break
        for i in range(len(nums)):
            if nums[i] + a==target:
                print('计算得出的下标是%s、%s,值分别是%s+%s=%s'% (indice-1,i+indice,a,nums[i],target))
                flag=False
                break
towSum([1,2,3,4,5,8,9],13)