Linux批量删除1到50个用户,Linux 批量添加/删除用户

本文介绍了一个shell脚本,用于批量添加和删除用户,通过选择选项输入用户名前缀、数量和密码,实现高效管理。

运行结果如下:

[root@server1 shell.sh]# ./useradd.sh

Please Input 1 or 2 :

1) Add User

2) Del User

#? 1

Please Input your username prefix:user

Please Input your user number:10

Please Enter your user password: 123

Add user1 Sucessful!

Add user2 Sucessful!

Add user3 Sucessful!

Add user4 Sucessful!

Add user5 Sucessful!

Add user6 Sucessful!

Add user7 Sucessful!

Add user8 Sucessful!

Add user9 Sucessful!

Add user10 Sucessful!

以下是脚本内容:

#!/bin/bash

#this scripts for batch add/del user

#DATE:2011/9/25 AUTHOR:LEO Email:411765588@qq.com

#if you are not root,exit

ID=$(id -u)

if [ $ID -ne 0 ];then

echo "Your are not root,only root can Add/Del

user"

exit 1

fi

#define variables

ADD="/usr/sbin/useradd"

DEL="/usr/sbin/userdel"

PASSWD="/usr/bin/passwd"

num=1

echo "Please Input 1 or 2 :"

select var in "Add User" "Del User"

do

break

done

read -p "Please Input your username prefix:" pre

read -p "Please Input your user number:" user_num

case $var in

"Add User")

read -p "Please Enter your user password: "

PW

while [ $num -le $user_num ]

do

if [ -e /home/$pre$num -o -e

/var/mail/$pre$num ]

then

echo "$pre$num already exists!!"

num=$(expr $num + 1)

else

$ADD

$pre$num && echo $PW | $PASSWD

--stdin $pre$num &>/dev/null

if [ $? =

0 ];then

echo

"Add $pre$num Sucessful!"

fi

num=$(expr

$num + 1)

fi

done

;;

"Del User")

while [ $num -le $user_num ]

do

$DEL -r

$pre$num &>/dev/null

&& echo "Delete $pre$num Sucessful"

|| echo "There is no $pre$num"

num=$(expr $num + 1)

done

;;

*)

echo "Invaild Input"

esac

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